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General equation of Kompassbrott's
1 min read
Let F0=z; F1=z^3+k*z^2+z; F[p]=F[p-1]^3+k*F[p-1]^2+z; whatever (p) natural number
the general equation of Kompassbrott's is this system of equation:
/ F[q]-F[r]=0
{
\ dF[q]/dz-dF[r]/dz=0
whatever q>r natural numbers, and F[p]=F[p](z,k) and for each (k) the (z) is kompassbrot point location for the cubic Mandelbrot set fc(v)=v^3+k*v^2+z if for the kompassbrot kind 1 location z=(-2*k^3-9*k)/27.
More details can be found on my channel on FRACTALFORUMS
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Other bug report
1 min read
DEVIANTART not longer support BMP files
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new gallery
1 min read
A new collection of Cubic Mandelbrot arrays and Cubic Julia arrays coming on my DA channel.
Hope to helpfull to exploring the secrets of cubic Mandelbrot sets.
Hope to helpfull to exploring the secrets of cubic Mandelbrot sets.
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New math function
1 min read
A new math function based by the Julia sets can opening a new branch of the math analysis (the functional equations).
For to can solve the equations like f(f(x))=x^2-1 where must to find f(x), existing a numerical method based of the infinity sums for the new function efP(z)= P (efP(z-1)) where P is a polynom, efP(-oo) is just the border of the Julia set determined by the polynom P, the Juliaset is JP={z|P(P(P...P(z)...))<>oo}. The infinity sum for efP(z+0.5) or for efP(z+i) can be rendered with the reccurence that is the sum for Q(Q(Q(Q...Q(z^(1/n))...))) where n=grad(P) and P(Q(z))=Q(P(z))=z.
More details can be founded at my channel on FRACTALFORUMS named (math research/new math function inspired from the Julia sets)
For to can solve the equations like f(f(x))=x^2-1 where must to find f(x), existing a numerical method based of the infinity sums for the new function efP(z)= P (efP(z-1)) where P is a polynom, efP(-oo) is just the border of the Julia set determined by the polynom P, the Juliaset is JP={z|P(P(P...P(z)...))<>oo}. The infinity sum for efP(z+0.5) or for efP(z+i) can be rendered with the reccurence that is the sum for Q(Q(Q(Q...Q(z^(1/n))...))) where n=grad(P) and P(Q(z))=Q(P(z))=z.
More details can be founded at my channel on FRACTALFORUMS named (math research/new math function inspired from the Julia sets)
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bug report
1 min read
Unfortunethly the servers of DEVIANTART are been attacked, due certain images don't show thumbnails with (404 not found error).
Be carefull with the user whick herassed me 10 years. I don't allow to say whick is user name because is against term and conditions, but I know that he is the hacker whick attacking servers, that he was attacked servers of FRACTALFORUMS 2 years ago, that admin of FRACTALFORUMS was forced to move all datas from WWW.FRACTALFORUMS.COM to new fresh site WWW.FRACTALFORUMS.ORG, and this hacker was destroyed the site WWW.FRACTALUS.COM adding malware content (this site can downloading unwanted malware program, issue for my antivirus seized this site) and own a program whick caused BSOD error with damage at my second computer, also this hacker hates all matematicians.
Hint: this hacker is from the staff of site WWW.RFRACTALS.NET
If perhaps my journal seem to be offensive. I can delete this comment.
Be carefull with the user whick herassed me 10 years. I don't allow to say whick is user name because is against term and conditions, but I know that he is the hacker whick attacking servers, that he was attacked servers of FRACTALFORUMS 2 years ago, that admin of FRACTALFORUMS was forced to move all datas from WWW.FRACTALFORUMS.COM to new fresh site WWW.FRACTALFORUMS.ORG, and this hacker was destroyed the site WWW.FRACTALUS.COM adding malware content (this site can downloading unwanted malware program, issue for my antivirus seized this site) and own a program whick caused BSOD error with damage at my second computer, also this hacker hates all matematicians.
Hint: this hacker is from the staff of site WWW.RFRACTALS.NET
If perhaps my journal seem to be offensive. I can delete this comment.
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